Artigo Acesso aberto Revisado por pares

Extensions and extremality of recursively generated weighted shifts

2001; American Mathematical Society; Volume: 130; Issue: 2 Linguagem: Inglês

10.1090/s0002-9939-01-06079-8

ISSN

1088-6826

Autores

Raúl E. Curto, Il Bong Jung, Woo Young Lee,

Tópico(s)

Advanced Banach Space Theory

Resumo

Given an $n$-step extension $\alpha :x_{n},\cdots ,x_{1},(\alpha _{0},\cdots ,\alpha _{k})^{\wedge }$ of a recursively generated weight sequence $(0<\alpha _{0}<\cdots <\alpha _{k})$, and if $W_{\alpha }$ denotes the associated unilateral weighted shift, we prove that \begin{equation*} W_{\alpha }\text { is subnormal } \Longleftrightarrow \begin {cases} \text {$W_\alpha $ is $([\frac {k+1}{2}]+1)$-hyponormal} & (n=1),\\ \text {$W_\alpha $ is $([\frac {k+1}{2}]+2)$-hyponormal} & (n>1). \end{cases} \end{equation*} In particular, the subnormality of an extension of a recursively generated weighted shift is independent of its length if the length is bigger than 1. As a consequence we see that if $\alpha (x)$ is a canonical rank-one perturbation of the recursive weight sequence $\alpha$, then subnormality and $k$-hyponormality for $W_{\alpha (x)}$ eventually coincide. We then examine a converse—an "extremality" problem: Let $\alpha (x)$ be a canonical rank-one perturbation of a weight sequence $\alpha$ and assume that $(k+1)$-hyponormality and $k$-hyponormality for $W_{\alpha (x)}$ coincide. We show that $\alpha (x)$ is recursively generated, i.e., $W_{\alpha (x)}$ is recursive subnormal.

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