Artigo Revisado por pares

Stabilization of Lithium Borohydride with Nitrogen Donor, Chelating Ligands. Syntheses and Solid State Structures of [HC(3,5-Me 2 pz) 3 ]Li(η 3 -BH 4 ), {[H 2 C(3,5-Me 2 pz) 2 ]Li(μ-η 3 -BH 4 )} 2 , and {[4,4‘-Me 2 bipy]Li(μ-η 3 -BH 4 )} 2 (pz = pyrazolyl, bipy = bipyridyl)

1997; American Chemical Society; Volume: 36; Issue: 27 Linguagem: Inglês

10.1021/ic970815h

ISSN

1520-510X

Autores

Daniel L. Reger, J. E. Collins, Michael A. Matthews, Arnold L. Rheingold, Louise M. Liable‐Sands, Ilia A. Guzei,

Tópico(s)

Radioactive element chemistry and processing

Resumo

The reaction of HC(3,5-Me2pz)3 and LiBH4 in THF yields [HC(3,5-Me2pz)3]Li(η3-BH4) (pz = pyrazolyl). In the solid state, the borohydride ligand is tridentate with an octahedral arrangement about the lithium. A similar reaction using HC(pz)3 yields the insoluble ionic compound {[HC(pz)3]2Li}(BH4). Reaction of equimolar amounts of LiBH4 and H2C(3,5-Me2pz)2 yields {[H2C(3,5-Me2pz)2]Li(μ-η3-BH4)}2. This complex is a centrosymmetric dimer in the solid state having two bridging [η3-BH4]- ligands. For each [η3-BH4]- ligand, there is one μ3-H and two μ2-H atoms. A similar reaction with H2C(pz)2 yields {[H2C(pz)2]Li(BH4)}2 and with 4,4‘-dimethyl-2,2‘-bipyridine (4,4‘-Me2bipy) yields {[4,4‘-Me2bipy]Li(μ-η3-BH4)}2. The structure of {[4,4‘-Me2bipy]Li(μ-η3-BH4)}2 in the solid state is similar to that of {[H2C(3,5-Me2pz)2]Li(μ-η3-BH4)}2, except the Li2B2 central core is not planar and both μ3-H atoms are on the same side of this core.

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