On the Differential Forms of the First Kind on Algebraic Varieties.
1949; Mathematical Society of Japan; Volume: 1; Issue: 3 Linguagem: Inglês
10.2969/jmsj/00130273
ISSN1881-1167
Autores Tópico(s)Advanced Topics in Algebra
ResumoIn his book' Foundations of algebraic geometry "J) A. Weil proposed several problems concerning differential forms on algebraic varieties.In this note we shall take up some of them.Especially we shall discuss differential forms of the first kind which are defined on a complete abstract varieties without multiple point.Here the field of dcfinition is assumed to be arbitrary.1. Let $K=k(x_{1},\ldots\ldots, x_{n})=k(x)$ be a field, generated over a field $k$ by a set $(x)$ of quantities; the totality $\mathfrak{D}$ of all derivations in $k(x)$ over $k$ forms a finite K-module.Every element 2 of $K$ d\'efines a linear functIon $d_{2}$ from $\mathfrak{D}$ into $K$ ; we call this linear function the differential of 2, and we can define multiplication between a differential and an element of $K$ as usual.The set $\mathfrak{F}$ of those linear functions, which are sums of the pro- ducts thus obtained, forms the dual K-module of $\mathfrak{D}$ , and therefore the di- mensions of $\mathfrak{D}$ and $\mathfrak{F}$ are equal.As usual we can form the Grassmann algebra from the finite K-module $\mathfrak{F}$ .An homogeneous element, of degree $m$ , is called a differential form of degree $m$, belonging to the extension $k(x)$ of $k$ .$PROPOS1TIO\Lambda^{7}1$ .Let $K=k(x)$ be a separably generated extention of $k$ , and $dim_{k}(x)=n$ .If $(u_{I}, \ldots.,u_{n})$ is a set of elements of $k(x)$ , such that $k(x)$ , such that $k(x)$ is separably algebraic over $k(u)$ , then every differential fom belonging to the extention $k(x)$ of $k$ can be expressed in one and only one way, as polynomials in $du_{1},\ldots\ldots,du_{n}$ with coefficients in $k(x)$ .PROOF.Let $z$ be an arbitrary element of $K$ ; it is sufficient to prove that $d_{2}$ is expressed uniquely as a linear form in $du_{1}\ldots\ldots.,du_{n}$ with coefficients in $k(x)$ .As 2 is separably algebric over $k(u)$ , there exists a polynomial $P(U, Z)$ in $k[U_{1},\ldots\ldots,U_{n}, Z]$ such that $ P(u, z)=0,.P_{Z}(u,z)\neq$ $0$ , During my investigation I have received kind criticisnis from Mr. Igusa to whom I express my hearty thanks.
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